6t-0.33t^2=0

Solution for 6t-0.33t^2=0 equation:

6t-0.33t^2=0

a = -0.33; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-0.33)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-0.33}=\frac{-12}{-0.66}
=18+0.12/0.66
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-0.33}=\frac{0}{-0.66}
=0
$